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3x^2=9^8
We move all terms to the left:
3x^2-(9^8)=0
We add all the numbers together, and all the variables
3x^2-43046721=0
a = 3; b = 0; c = -43046721;
Δ = b2-4ac
Δ = 02-4·3·(-43046721)
Δ = 516560652
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{516560652}=\sqrt{172186884*3}=\sqrt{172186884}*\sqrt{3}=13122\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-13122\sqrt{3}}{2*3}=\frac{0-13122\sqrt{3}}{6} =-\frac{13122\sqrt{3}}{6} =-2187\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+13122\sqrt{3}}{2*3}=\frac{0+13122\sqrt{3}}{6} =\frac{13122\sqrt{3}}{6} =2187\sqrt{3} $
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